Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Both sides previous revision Previous revision
Next revision 		Previous revision
Next revision Both sides next revision
birds_databaser [2014-04-14 20:56]
Joakim Forsgren 		birds_databaser [2015-04-24 13:14]
Joakim Forsgren
Line 43: Line 43:
 </code> </code>
   - Gör om frågan så att man bara ser de fåglar som JF har fler än 4 observationer av.   - Gör om frågan så att man bara ser de fåglar som JF har fler än 4 observationer av.
-  - Gör om frågan så att man bara ser de fåglar som JF har 1 observation av.+  - Gör om frågan så att man bara ser de fåglar som JF har 1 observation av.<code> 
 +Nu börjar det bli svårt...</code>
   - Skriv en fråga som tar fram hur många olika fågelarter varje användare har. Tips: COUNT (DISTINCT… Ex på lämpligt svar:<code>   - Skriv en fråga som tar fram hur många olika fågelarter varje användare har. Tips: COUNT (DISTINCT… Ex på lämpligt svar:<code>
 +-----------+-----------------+-------+ +-----------+-----------------+-------+
Line 107: Line 108:
 SELECT * FROM Birds; SELECT * FROM Birds;
  
-2.+9.
 SELECT * FROM Observations  SELECT * FROM Observations 
 WHERE UserID=3; WHERE UserID=3;
  
-3.+10.
 SELECT * FROM Users INNER JOIN Observations USING(UserID) SELECT * FROM Users INNER JOIN Observations USING(UserID)
 WHERE Login='JF'; WHERE Login='JF';
  
-4.+11.
 SELECT Name,COUNT(UserID) as Antal  SELECT Name,COUNT(UserID) as Antal 
 FROM Birds INNER JOIN Observations USING(BirdID)  FROM Birds INNER JOIN Observations USING(BirdID) 
Line 122: Line 123:
 ORDER BY Antal DESC; ORDER BY Antal DESC;
  
-SELECT Name,COUNT(UserID) as Antal  FROM Birds INNER JOIN Observations USING(BirdID)  WHERE UserID=1  GROUP BY BirdID  having Antal>4 ORDER BY Antal DESC;+12. 
 +SELECT Name,COUNT(UserID) as Antal  FROM Birds INNER JOIN Observations USING(BirdID)  WHERE UserID=3  GROUP BY BirdID  having Antal>4 ORDER BY Antal DESC;
  
-5.+14.
 SELECT CONCAT(FirstName,' ',LastName) as Name,COUNT(DISTINCT BirdID) as Antal  SELECT CONCAT(FirstName,' ',LastName) as Name,COUNT(DISTINCT BirdID) as Antal 
 FROM Users INNER JOIN Observations USING(UserID)  FROM Users INNER JOIN Observations USING(UserID) 
Line 130: Line 132:
 ORDER BY Antal DESC; ORDER BY Antal DESC;
  
-6.+15.
 SELECT Name,COUNT(DISTINCT UserID) as Antal  SELECT Name,COUNT(DISTINCT UserID) as Antal 
 FROM Birds INNER JOIN Observations USING(BirdID)  FROM Birds INNER JOIN Observations USING(BirdID) 
Line 136: Line 138:
 GROUP BY BirdID ORDER BY Antal DESC; GROUP BY BirdID ORDER BY Antal DESC;
  
-7.+16.
 SELECT CONCAT(FirstName,' ',LastName) as Name,COUNT(DISTINCT BirdID) as Antal  SELECT CONCAT(FirstName,' ',LastName) as Name,COUNT(DISTINCT BirdID) as Antal 
 FROM Users INNER JOIN Observations USING(UserID)  FROM Users INNER JOIN Observations USING(UserID)